1876. Substrings of Size Three with Distinct Characters
Topic Easy
Area Algorithms
Problem
Difficulty: Easy
Tags: Mid Level, Hash Table, String, Sliding Window, Counting, Biweekly Contest 53
Intuition
This question is much easier than previous question. I could do check all the possible substrings of length 3, and it wasn’t that slow.
if 3 gets bigger to like 10 or 100, I might do with different method, but for this problem, checking every combination was fine.
Approach
let i be idex of first element of substring with length 3, and check every possible substring by increasing i by 1.
Solution
class Solution:
def countGoodSubstrings(self, s: str) -> int:
if len(s) < 3:
return 0
count = 0
i = 0
while i+3 <= len(s):
if not(s[i] == s[i+1] or s[i] == s[i+2] or s[i+1] == s[i+2]):
count += 1
i += 1
return count
Complexity
-
Time:
-
Space:
Thoughts
This one was easy.